BitSet

Creates a new BitSet with size equal to 64 bits.

Creates a new BitSet with size equal to bitCount , rounded up to a multiple of 64.

Logically ands the bits of this BitSet with bs .

Clears all bits in this BitSet which are also set in bs .

Returns the number of bits that are true in this BitSet .

Clears the bit at index index .

Clears all the bits in this BitSet . This method does not change the capacity. Use clear if you want to reuse this BitSet with the same capacity, but create a new BitSet if you're trying to potentially reclaim memory.

Clears the range of bits [fromIndex, toIndex) .

Creates and returns a copy of this Object . The default implementation returns a so-called "shallow" copy: It creates a new instance of the same class and then copies the field values (including object references) from this instance to the new instance. A "deep" copy, in contrast, would also recursively clone nested objects. A subclass that needs to implement this kind of cloning should call super.clone() to create the new instance and then create deep copies of the nested, mutable objects.

Compares this instance with the specified object and indicates if they are equal. In order to be equal, o must represent the same object as this instance using a class-specific comparison. The general contract is that this comparison should be reflexive, symmetric, and transitive. Also, no object reference other than null is equal to null.

The default implementation returns true only if this == o . See Writing a correct equals method if you intend implementing your own equals method.

The general contract for the equals and hashCode() methods is that if equals returns true for any two objects, then hashCode() must return the same value for these objects. This means that subclasses of Object usually override either both methods or neither of them.

Flips the bit at index index .

Flips the range of bits [fromIndex, toIndex) .

Returns the bit at index index . Indexes greater than the current length return false.

Returns a new BitSet containing the range of bits [fromIndex, toIndex) , shifted down so that the bit at fromIndex is at bit 0 in the new BitSet .

Returns an integer hash code for this object. By contract, any two objects for which equals(Object) returns true must return the same hash code value. This means that subclasses of Object usually override both methods or neither method.

Note that hash values must not change over time unless information used in equals comparisons also changes.

See Writing a correct hashCode method if you intend implementing your own hashCode method.

Returns true if this.and(bs) is non-empty, but may be faster than computing that.

Returns true if all the bits in this BitSet are set to false, false otherwise.

Returns the number of bits up to and including the highest bit set. This is unrelated to the size() of the BitSet .

Returns the index of the first bit that is clear on or after index . Since all bits past the end are implicitly clear, this never returns -1.

Returns the index of the first bit that is set on or after index , or -1 if no higher bits are set.

Logically ors the bits of this BitSet with bs .

Returns the index of the first bit that is clear on or before index , or -1 if no lower bits are clear or index == -1 .

Returns the index of the first bit that is set on or before index , or -1 if no lower bits are set or index == -1 .

Sets the bit at index index to state .

Sets the range of bits [fromIndex, toIndex) to state .

Sets the range of bits [fromIndex, toIndex) .

Sets the bit at index index to true.

Returns the capacity in bits of the array implementing this BitSet . This is unrelated to the length of the BitSet , and not generally useful. Use nextSetBit(int) to iterate, or length() to find the highest set bit.

Returns a new byte[] containing a little-endian representation the bits of this BitSet , suitable for passing to valueOf to reconstruct this BitSet .

Returns a new long[] containing a little-endian representation of the bits of this BitSet , suitable for passing to valueOf to reconstruct this BitSet .

Returns a string containing a concise, human-readable description of the receiver: a comma-delimited list of the indexes of all set bits. For example: "{0,1,8 "}.

Equivalent to BitSet.valueOf(ByteBuffer.wrap(bytes)) .

Returns a BitSet corresponding to byteBuffer , interpreted as a little-endian sequence of bits. This method does not alter the ByteBuffer .

Returns a BitSet corresponding to longBuffer , interpreted as a little-endian sequence of bits. This method does not alter the LongBuffer .

Equivalent to BitSet.valueOf(LongBuffer.wrap(longs)) , but likely to be faster. This is likely to be the fastest way to create a BitSet because it's closest to the internal representation.

Logically xors the bits of this BitSet with bs .